The reaction sequence is as follows:Benzene + | vedclass

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(D) $1$. The reaction of benzene with $CH_3COCl$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts acylation reaction,which produces acetophen

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All of the above

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(D) $1$. The reaction of benzene with $CH_3COCl$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts acylation reaction,which produces acetophenone $(A)$ as the product $(C_6H_5COCH_3)$.$2$. The conversion of acetophenone to ethylbenzene $(C_6H_5CH_2CH_3)$ involves the reduction of the carbonyl group $(>C=O)$ to a methylene group $(>CH_2)$.$3$. The reagents listed are all standard methods for the reduction of carbonyl compounds to alkanes:- $HI / 	ext{Red } P$ is a strong reducing agent that reduces carbonyl groups to methylene groups.- $Zn-Hg / HCl$ is the reagent for Clemmensen reduction,which reduces ketones to alkanes.- $NH_2-NH_2 / \overset{\Theta}{O}H / \Delta$ is the reagent for Wolff-Kishner reduction,which also reduces ketones to alkanes.$4$. Since all three reagents can perform this transformation,the correct answer is 'All of the above'.

Column-$I$ (Reactants)	Column-$II$ (Products)
$(A)$ $HCHO + \text{Cyclohexyl-MgBr} \rightarrow X \xrightarrow{H_2O} Y$	$(i)$ $\text{Benzenesulfonic acid}$
$(B)$ $\text{2-oxocyclohexylacetate} \xrightarrow{NaBH_4}$	$(ii)$ $\text{Cyclohexylmethanol}$
$(C)$ $HCHO + CH_3-CH_2-CH(CH_3)-CH_2-MgBr \rightarrow X \xrightarrow{H_2O} Y$	$(iii)$ $\text{2-(2-hydroxycyclohexyl)acetate}$
$(D)$ $\text{Benzene} + \text{Oleum}$	$(iv)$ $Y = \text{3-methylpentan-1-ol}$

The reaction sequence is as follows:
Benzene + $CH_3COCl$ $\xrightarrow{\text{Anhydrous } AlCl_3} (A)$ $\xrightarrow{(x)} \text{Ethylbenzene}$.
Reagent $(x)$ can be:

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The reaction sequence is as follows:Benzene + $CH_3COCl$ $\xrightarrow{\text{Anhydrous } AlCl_3} (A)$ $\xrightarrow{(x)} \text{Ethylbenzene}$.Reagent $(x)$ can be: